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21534350214535 = 54306870042907
BaseRepresentation
bin1001110010101110110110…
…10010111000010110000111
32211020122220220002100020021
410321113123102320112013
510310304322123331120
6113444424404120011
74351543162452334
oct471273322702607
984218826070207
1021534350214535
116952737329a84
1224b9602396007
13c028b0113872
145463a79ab98b
15275257c0baaa
hex1395db4b8587

21534350214535 has 4 divisors (see below), whose sum is σ = 25841220257448. Its totient is φ = 17227480171624.

The previous prime is 21534350214511. The next prime is 21534350214539. The reversal of 21534350214535 is 53541205343512.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21534350214535 - 27 = 21534350214407 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21534350214491 and 21534350214500.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21534350214539) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2153435021449 + ... + 2153435021458.

It is an arithmetic number, because the mean of its divisors is an integer number (6460305064362).

Almost surely, 221534350214535 is an apocalyptic number.

21534350214535 is a deficient number, since it is larger than the sum of its proper divisors (4306870042913).

21534350214535 is an equidigital number, since it uses as much as digits as its factorization.

21534350214535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4306870042912.

The product of its (nonzero) digits is 1080000, while the sum is 43.

The spelling of 21534350214535 in words is "twenty-one trillion, five hundred thirty-four billion, three hundred fifty million, two hundred fourteen thousand, five hundred thirty-five".

Divisors: 1 5 4306870042907 21534350214535