Base | Representation |
---|---|
bin | 1001110010101110110110… |
… | …10010111000010110001011 |
3 | 2211020122220220002100020102 |
4 | 10321113123102320112023 |
5 | 10310304322123331124 |
6 | 113444424404120015 |
7 | 4351543162452341 |
oct | 471273322702613 |
9 | 84218826070212 |
10 | 21534350214539 |
11 | 6952737329a88 |
12 | 24b960239600b |
13 | c028b0113876 |
14 | 5463a79ab991 |
15 | 275257c0baae |
hex | 1395db4b858b |
21534350214539 has 2 divisors, whose sum is σ = 21534350214540. Its totient is φ = 21534350214538.
The previous prime is 21534350214511. The next prime is 21534350214541. The reversal of 21534350214539 is 93541205343512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21534350214539 - 28 = 21534350214283 is a prime.
Together with 21534350214541, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 21534350214493 and 21534350214502.
It is not a weakly prime, because it can be changed into another prime (21534350214569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10767175107269 + 10767175107270.
It is an arithmetic number, because the mean of its divisors is an integer number (10767175107270).
Almost surely, 221534350214539 is an apocalyptic number.
21534350214539 is a deficient number, since it is larger than the sum of its proper divisors (1).
21534350214539 is an equidigital number, since it uses as much as digits as its factorization.
21534350214539 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944000, while the sum is 47.
The spelling of 21534350214539 in words is "twenty-one trillion, five hundred thirty-four billion, three hundred fifty million, two hundred fourteen thousand, five hundred thirty-nine".
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