Base | Representation |
---|---|
bin | 10100000011100011… |
… | …100011101000011001 |
3 | 2001120202221101120212 |
4 | 110003203203220121 |
5 | 323100312122423 |
6 | 13520502500505 |
7 | 1361434065044 |
oct | 240343435031 |
9 | 61522841525 |
10 | 21534489113 |
11 | 9150726445 |
12 | 420ba34735 |
13 | 2052584267 |
14 | 1084005c5b |
15 | 860829578 |
hex | 5038e3a19 |
21534489113 has 2 divisors, whose sum is σ = 21534489114. Its totient is φ = 21534489112.
The previous prime is 21534489089. The next prime is 21534489131. The reversal of 21534489113 is 31198443512.
Together with next prime (21534489131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18899925529 + 2634563584 = 137477^2 + 51328^2 .
It is a cyclic number.
It is not a de Polignac number, because 21534489113 - 216 = 21534423577 is a prime.
It is not a weakly prime, because it can be changed into another prime (21534489143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10767244556 + 10767244557.
It is an arithmetic number, because the mean of its divisors is an integer number (10767244557).
Almost surely, 221534489113 is an apocalyptic number.
It is an amenable number.
21534489113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21534489113 is an equidigital number, since it uses as much as digits as its factorization.
21534489113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 103680, while the sum is 41.
The spelling of 21534489113 in words is "twenty-one billion, five hundred thirty-four million, four hundred eighty-nine thousand, one hundred thirteen".
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