Base | Representation |
---|---|
bin | 1000000001100000… |
… | …1111101101001001 |
3 | 12120002211101020212 |
4 | 2000120033231021 |
5 | 13402340330213 |
6 | 553420130505 |
7 | 104242222154 |
oct | 20030175511 |
9 | 5502741225 |
10 | 2153839433 |
11 | a05871499 |
12 | 501396a35 |
13 | 2842bba05 |
14 | 1660a2c9b |
15 | c914e9a8 |
hex | 8060fb49 |
2153839433 has 2 divisors, whose sum is σ = 2153839434. Its totient is φ = 2153839432.
The previous prime is 2153839417. The next prime is 2153839453. The reversal of 2153839433 is 3349383512.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1700490169 + 453349264 = 41237^2 + 21292^2 .
It is a cyclic number.
It is not a de Polignac number, because 2153839433 - 24 = 2153839417 is a prime.
It is a super-2 number, since 2×21538394332 = 9278048606291522978, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2153839453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076919716 + 1076919717.
It is an arithmetic number, because the mean of its divisors is an integer number (1076919717).
Almost surely, 22153839433 is an apocalyptic number.
It is an amenable number.
2153839433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2153839433 is an equidigital number, since it uses as much as digits as its factorization.
2153839433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 233280, while the sum is 41.
The square root of 2153839433 is about 46409.4756811580. The cubic root of 2153839433 is about 1291.4307049864.
The spelling of 2153839433 in words is "two billion, one hundred fifty-three million, eight hundred thirty-nine thousand, four hundred thirty-three".
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