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2153913403 is a prime number
BaseRepresentation
bin1000000001100010…
…0001110000111011
312120002222010201111
42000120201300323
513402400212103
6553421501151
7104242650625
oct20030416073
95502863644
102153913403
11a05912024
125014117b7
13284316595
141660c1c15
15c916686d
hex80621c3b

2153913403 has 2 divisors, whose sum is σ = 2153913404. Its totient is φ = 2153913402.

The previous prime is 2153913383. The next prime is 2153913427. The reversal of 2153913403 is 3043193512.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2153913403 - 213 = 2153905211 is a prime.

It is not a weakly prime, because it can be changed into another prime (2153923403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1076956701 + 1076956702.

It is an arithmetic number, because the mean of its divisors is an integer number (1076956702).

Almost surely, 22153913403 is an apocalyptic number.

2153913403 is a deficient number, since it is larger than the sum of its proper divisors (1).

2153913403 is an equidigital number, since it uses as much as digits as its factorization.

2153913403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 31.

The square root of 2153913403 is about 46410.2726020867. The cubic root of 2153913403 is about 1291.4454888238.

The spelling of 2153913403 in words is "two billion, one hundred fifty-three million, nine hundred thirteen thousand, four hundred three".