Base | Representation |
---|---|
bin | 1100100010011110100… |
… | …0100100111001111111 |
3 | 202121000112011010020110 |
4 | 3020213220210321333 |
5 | 12012131302010101 |
6 | 242543130521103 |
7 | 21364066644021 |
oct | 3104750447177 |
9 | 677015133213 |
10 | 215413313151 |
11 | 833a1221533 |
12 | 358b9596193 |
13 | 1740c68b40a |
14 | a5d7174011 |
15 | 590b6cbcd6 |
hex | 3227a24e7f |
215413313151 has 4 divisors (see below), whose sum is σ = 287217750872. Its totient is φ = 143608875432.
The previous prime is 215413313131. The next prime is 215413313177. The reversal of 215413313151 is 151313314512.
It is a semiprime because it is the product of two primes.
It is a de Polignac number, because none of the positive numbers 2k-215413313151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (215413313131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35902218856 + ... + 35902218861.
It is an arithmetic number, because the mean of its divisors is an integer number (71804437718).
Almost surely, 2215413313151 is an apocalyptic number.
215413313151 is a deficient number, since it is larger than the sum of its proper divisors (71804437721).
215413313151 is an equidigital number, since it uses as much as digits as its factorization.
215413313151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71804437720.
The product of its digits is 5400, while the sum is 30.
Adding to 215413313151 its reverse (151313314512), we get a palindrome (366726627663).
The spelling of 215413313151 in words is "two hundred fifteen billion, four hundred thirteen million, three hundred thirteen thousand, one hundred fifty-one".
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