Base | Representation |
---|---|
bin | 1100100010100101000… |
… | …0010101100000001011 |
3 | 202121002102100000110120 |
4 | 3020221100111200023 |
5 | 12012210232404120 |
6 | 242545541514323 |
7 | 21364550100666 |
oct | 3105120254013 |
9 | 677072300416 |
10 | 215440513035 |
11 | 8340560a180 |
12 | 359067129a3 |
13 | 174151c2a17 |
14 | a5daa146dd |
15 | 590dca1140 |
hex | 322941580b |
215440513035 has 64 divisors (see below), whose sum is σ = 399871779840. Its totient is φ = 97889300480.
The previous prime is 215440513031. The next prime is 215440513051. The reversal of 215440513035 is 530315044512.
It is not a de Polignac number, because 215440513035 - 22 = 215440513031 is a prime.
It is a super-2 number, since 2×2154405130352 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 215440512987 and 215440513005.
It is not an unprimeable number, because it can be changed into a prime (215440513031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 488746 + ... + 818384.
It is an arithmetic number, because the mean of its divisors is an integer number (6247996560).
Almost surely, 2215440513035 is an apocalyptic number.
215440513035 is a deficient number, since it is larger than the sum of its proper divisors (184431266805).
215440513035 is a wasteful number, since it uses less digits than its factorization.
215440513035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 329908.
The product of its (nonzero) digits is 36000, while the sum is 33.
Adding to 215440513035 its reverse (530315044512), we get a palindrome (745755557547).
The spelling of 215440513035 in words is "two hundred fifteen billion, four hundred forty million, five hundred thirteen thousand, thirty-five".
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