2154412433 has 2 divisors, whose sum is σ = 2154412434. Its totient is φ = 2154412432.

The previous prime is 2154412399. The next prime is 2154412441. The reversal of 2154412433 is 3342144512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1851408784 + 303003649 = 43028^2 + 17407^2 .

It is a cyclic number.

It is not a de Polignac number, because 2154412433 - 2¹⁶ = 2154346897 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2154412396 and 2154412405.

It is not a weakly prime, because it can be changed into another prime (2154412493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077206216 + 1077206217.

It is an arithmetic number, because the mean of its divisors is an integer number (1077206217).

Almost surely, 2^2154412433 is an apocalyptic number.

It is an amenable number.

2154412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2154412433 is an equidigital number, since it uses as much as digits as its factorization.

2154412433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 11520, while the sum is 29.

The square root of 2154412433 is about 46415.6485789006. The cubic root of 2154412433 is about 1291.5452174195.

Adding to 2154412433 its reverse (3342144512), we get a palindrome (5496556945).

The spelling of 2154412433 in words is "two billion, one hundred fifty-four million, four hundred twelve thousand, four hundred thirty-three".