Base | Representation |
---|---|
bin | 110000111111101010101100… |
… | …010110011110110101111011 |
3 | 1001020221211011022112122200201 |
4 | 300333222230112132311323 |
5 | 211220421402102034341 |
6 | 2042142442225143031 |
7 | 63250005663105454 |
oct | 6077525426366573 |
9 | 1036854138478621 |
10 | 215481400814971 |
11 | 62728170198325 |
12 | 202018a518aa77 |
13 | 9330a692271a5 |
14 | 3b2d4d94bc12b |
15 | 19da274572331 |
hex | c3faac59ed7b |
215481400814971 has 2 divisors, whose sum is σ = 215481400814972. Its totient is φ = 215481400814970.
The previous prime is 215481400814843. The next prime is 215481400814989. The reversal of 215481400814971 is 179418004184512.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 215481400814971 - 27 = 215481400814843 is a prime.
It is not a weakly prime, because it can be changed into another prime (215481400814171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107740700407485 + 107740700407486.
It is an arithmetic number, because the mean of its divisors is an integer number (107740700407486).
Almost surely, 2215481400814971 is an apocalyptic number.
215481400814971 is a deficient number, since it is larger than the sum of its proper divisors (1).
215481400814971 is an equidigital number, since it uses as much as digits as its factorization.
215481400814971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2580480, while the sum is 55.
The spelling of 215481400814971 in words is "two hundred fifteen trillion, four hundred eighty-one billion, four hundred million, eight hundred fourteen thousand, nine hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •