Base | Representation |
---|---|
bin | 1001110011001100001111… |
… | …11011011110100110101001 |
3 | 2211022011122201020122211211 |
4 | 10321212013323132212221 |
5 | 10311034132122040131 |
6 | 113455554350353121 |
7 | 4352642226612211 |
oct | 471460773364651 |
9 | 84264581218754 |
10 | 21550131440041 |
11 | 69593a5429306 |
12 | 25006874bb7a1 |
13 | c0422676b119 |
14 | 547063871241 |
15 | 27587d3da5b1 |
hex | 139987ede9a9 |
21550131440041 has 2 divisors, whose sum is σ = 21550131440042. Its totient is φ = 21550131440040.
The previous prime is 21550131439999. The next prime is 21550131440051. The reversal of 21550131440041 is 14004413105512.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 17167929296400 + 4382202143641 = 4143420^2 + 2093371^2 .
It is a cyclic number.
It is not a de Polignac number, because 21550131440041 - 225 = 21550097885609 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21550131439985 and 21550131440012.
It is not a weakly prime, because it can be changed into another prime (21550131440051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10775065720020 + 10775065720021.
It is an arithmetic number, because the mean of its divisors is an integer number (10775065720021).
Almost surely, 221550131440041 is an apocalyptic number.
It is an amenable number.
21550131440041 is a deficient number, since it is larger than the sum of its proper divisors (1).
21550131440041 is an equidigital number, since it uses as much as digits as its factorization.
21550131440041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 21550131440041 its reverse (14004413105512), we get a palindrome (35554544545553).
The spelling of 21550131440041 in words is "twenty-one trillion, five hundred fifty billion, one hundred thirty-one million, four hundred forty thousand, forty-one".
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