Base | Representation |
---|---|
bin | 1001110011010000011110… |
… | …01101010111100101001111 |
3 | 2211022101111212220222221020 |
4 | 10321220033031113211033 |
5 | 10311103304132212111 |
6 | 113501011504205223 |
7 | 4353052406166501 |
oct | 471501715274517 |
9 | 84271455828836 |
10 | 21552401054031 |
11 | 695a35a585951 |
12 | 2500bbb609813 |
13 | c044c8a34693 |
14 | 5471db06dd71 |
15 | 2759627a8906 |
hex | 139a0f35794f |
21552401054031 has 32 divisors (see below), whose sum is σ = 29488252953600. Its totient is φ = 13993626366720.
The previous prime is 21552401054011. The next prime is 21552401054069. The reversal of 21552401054031 is 13045010425512.
It is not a de Polignac number, because 21552401054031 - 25 = 21552401053999 is a prime.
It is a super-2 number, since 2×215524010540312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21552401053983 and 21552401054001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21552401054011) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 506034285 + ... + 506076873.
It is an arithmetic number, because the mean of its divisors is an integer number (921507904800).
Almost surely, 221552401054031 is an apocalyptic number.
21552401054031 is a deficient number, since it is larger than the sum of its proper divisors (7935851899569).
21552401054031 is a wasteful number, since it uses less digits than its factorization.
21552401054031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49639.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 21552401054031 its reverse (13045010425512), we get a palindrome (34597411479543).
The spelling of 21552401054031 in words is "twenty-one trillion, five hundred fifty-two billion, four hundred one million, fifty-four thousand, thirty-one".
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