Base | Representation |
---|---|
bin | 1001110011010010010101… |
… | …10101000011110011100110 |
3 | 2211022111002121002111101112 |
4 | 10321221022311003303212 |
5 | 10311112331214031114 |
6 | 113501255035225022 |
7 | 4353116243234045 |
oct | 471511265036346 |
9 | 84274077074345 |
10 | 21553401314534 |
11 | 695a823167421 |
12 | 250123a5a8172 |
13 | c046280332bb |
14 | 547293c4855c |
15 | 2759c04dc13e |
hex | 139a4ad43ce6 |
21553401314534 has 4 divisors (see below), whose sum is σ = 32330101971804. Its totient is φ = 10776700657266.
The previous prime is 21553401314531. The next prime is 21553401314593. The reversal of 21553401314534 is 43541310435512.
It is a semiprime because it is the product of two primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 21553401314491 and 21553401314500.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21553401314531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5388350328632 + ... + 5388350328635.
It is an arithmetic number, because the mean of its divisors is an integer number (8082525492951).
Almost surely, 221553401314534 is an apocalyptic number.
21553401314534 is a deficient number, since it is larger than the sum of its proper divisors (10776700657270).
21553401314534 is a wasteful number, since it uses less digits than its factorization.
21553401314534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10776700657269.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 21553401314534 in words is "twenty-one trillion, five hundred fifty-three billion, four hundred one million, three hundred fourteen thousand, five hundred thirty-four".
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