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2155632612017 is a prime number
BaseRepresentation
bin11111010111100101101…
…101110101001010110001
321122002001202001200221112
4133113211231311022301
5240304213422041032
64330141200003105
7311511404610503
oct37274555651261
97562052050845
102155632612017
11761220459795
122a9939000495
13128376a48b41
1476494337d73
153b1163241b2
hex1f5e5b752b1

2155632612017 has 2 divisors, whose sum is σ = 2155632612018. Its totient is φ = 2155632612016.

The previous prime is 2155632611969. The next prime is 2155632612047. The reversal of 2155632612017 is 7102162365512.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1519835289856 + 635797322161 = 1232816^2 + 797369^2 .

It is a cyclic number.

It is not a de Polignac number, because 2155632612017 - 28 = 2155632611761 is a prime.

It is not a weakly prime, because it can be changed into another prime (2155632612047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1077816306008 + 1077816306009.

It is an arithmetic number, because the mean of its divisors is an integer number (1077816306009).

Almost surely, 22155632612017 is an apocalyptic number.

It is an amenable number.

2155632612017 is a deficient number, since it is larger than the sum of its proper divisors (1).

2155632612017 is an equidigital number, since it uses as much as digits as its factorization.

2155632612017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 41.

Adding to 2155632612017 its reverse (7102162365512), we get a palindrome (9257794977529).

The spelling of 2155632612017 in words is "two trillion, one hundred fifty-five billion, six hundred thirty-two million, six hundred twelve thousand, seventeen".