Base | Representation |
---|---|
bin | 11111010111100110000… |
… | …110101110001101011111 |
3 | 21122002002012100012200222 |
4 | 133113212012232031133 |
5 | 240304222104341434 |
6 | 4330141551511555 |
7 | 311511514225226 |
oct | 37274606561537 |
9 | 7562065305628 |
10 | 2155639137119 |
11 | 761224106136 |
12 | 2a993b2285bb |
13 | 1283781c1b50 |
14 | 76495155cbd |
15 | 3b116bb272e |
hex | 1f5e61ae35f |
2155639137119 has 4 divisors (see below), whose sum is σ = 2321457532296. Its totient is φ = 1989820741944.
The previous prime is 2155639137023. The next prime is 2155639137121. The reversal of 2155639137119 is 9117319365512.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2155639137119 - 220 = 2155638088543 is a prime.
It is a super-3 number, since 3×21556391371193 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2155639137199) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82909197569 + ... + 82909197594.
It is an arithmetic number, because the mean of its divisors is an integer number (580364383074).
Almost surely, 22155639137119 is an apocalyptic number.
2155639137119 is a deficient number, since it is larger than the sum of its proper divisors (165818395177).
2155639137119 is a wasteful number, since it uses less digits than its factorization.
2155639137119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 165818395176.
The product of its digits is 1530900, while the sum is 53.
The spelling of 2155639137119 in words is "two trillion, one hundred fifty-five billion, six hundred thirty-nine million, one hundred thirty-seven thousand, one hundred nineteen".
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