Base | Representation |
---|---|
bin | 11111011000010110011… |
… | …100001000101101011011 |
3 | 21122011011201020012201112 |
4 | 133120112130020231123 |
5 | 240312402203311201 |
6 | 4330354240410535 |
7 | 311540562022253 |
oct | 37302634105533 |
9 | 7564151205645 |
10 | 2156450057051 |
11 | 7615aa9252a4 |
12 | 2a9b26916a4b |
13 | 1284771c9224 |
14 | 76530b24963 |
15 | 3b162e950bb |
hex | 1f616708b5b |
2156450057051 has 2 divisors, whose sum is σ = 2156450057052. Its totient is φ = 2156450057050.
The previous prime is 2156450056991. The next prime is 2156450057071. The reversal of 2156450057051 is 1507500546512.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2156450057051 is a prime.
It is a super-2 number, since 2×21564500570512 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2156450057071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1078225028525 + 1078225028526.
It is an arithmetic number, because the mean of its divisors is an integer number (1078225028526).
Almost surely, 22156450057051 is an apocalyptic number.
2156450057051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2156450057051 is an equidigital number, since it uses as much as digits as its factorization.
2156450057051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 210000, while the sum is 41.
The spelling of 2156450057051 in words is "two trillion, one hundred fifty-six billion, four hundred fifty million, fifty-seven thousand, fifty-one".
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