Base | Representation |
---|---|
bin | 11111011101010000011… |
… | …000011110011110001001 |
3 | 21122122202210011220220221 |
4 | 133131100120132132021 |
5 | 240404144042042213 |
6 | 4333025032350041 |
7 | 312115236354241 |
oct | 37352030363611 |
9 | 7578683156827 |
10 | 2161717143433 |
11 | 763862a76251 |
12 | 2aab56845321 |
13 | 128b064a06a3 |
14 | 768b046cb21 |
15 | 3b3705a838d |
hex | 1f75061e789 |
2161717143433 has 2 divisors, whose sum is σ = 2161717143434. Its totient is φ = 2161717143432.
The previous prime is 2161717143413. The next prime is 2161717143461. The reversal of 2161717143433 is 3343417171612.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1905871364089 + 255845779344 = 1380533^2 + 505812^2 .
It is a cyclic number.
It is not a de Polignac number, because 2161717143433 - 213 = 2161717135241 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2161717143433.
It is not a weakly prime, because it can be changed into another prime (2161717143413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1080858571716 + 1080858571717.
It is an arithmetic number, because the mean of its divisors is an integer number (1080858571717).
Almost surely, 22161717143433 is an apocalyptic number.
It is an amenable number.
2161717143433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2161717143433 is an equidigital number, since it uses as much as digits as its factorization.
2161717143433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 254016, while the sum is 43.
The spelling of 2161717143433 in words is "two trillion, one hundred sixty-one billion, seven hundred seventeen million, one hundred forty-three thousand, four hundred thirty-three".
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