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2161717143433 is a prime number
BaseRepresentation
bin11111011101010000011…
…000011110011110001001
321122122202210011220220221
4133131100120132132021
5240404144042042213
64333025032350041
7312115236354241
oct37352030363611
97578683156827
102161717143433
11763862a76251
122aab56845321
13128b064a06a3
14768b046cb21
153b3705a838d
hex1f75061e789

2161717143433 has 2 divisors, whose sum is σ = 2161717143434. Its totient is φ = 2161717143432.

The previous prime is 2161717143413. The next prime is 2161717143461. The reversal of 2161717143433 is 3343417171612.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1905871364089 + 255845779344 = 1380533^2 + 505812^2 .

It is a cyclic number.

It is not a de Polignac number, because 2161717143433 - 213 = 2161717135241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2161717143433.

It is not a weakly prime, because it can be changed into another prime (2161717143413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1080858571716 + 1080858571717.

It is an arithmetic number, because the mean of its divisors is an integer number (1080858571717).

Almost surely, 22161717143433 is an apocalyptic number.

It is an amenable number.

2161717143433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2161717143433 is an equidigital number, since it uses as much as digits as its factorization.

2161717143433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 254016, while the sum is 43.

The spelling of 2161717143433 in words is "two trillion, one hundred sixty-one billion, seven hundred seventeen million, one hundred forty-three thousand, four hundred thirty-three".