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2162034702433 is a prime number
BaseRepresentation
bin11111011101100011010…
…011110111100001100001
321122200120220201120222101
4133131203103313201201
5240410321340434213
64333120335010401
7312126143515234
oct37354323674141
97580526646871
102162034702433
11763a06253001
122ab025069a01
13128b57208818
14769006d341b
153b38d3d4bdd
hex1f7634f7861

2162034702433 has 2 divisors, whose sum is σ = 2162034702434. Its totient is φ = 2162034702432.

The previous prime is 2162034702391. The next prime is 2162034702473. The reversal of 2162034702433 is 3342074302612.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2093134752289 + 68899950144 = 1446767^2 + 262488^2 .

It is a cyclic number.

It is not a de Polignac number, because 2162034702433 - 225 = 2162001148001 is a prime.

It is a super-2 number, since 2×21620347024332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2162034702392 and 2162034702401.

It is not a weakly prime, because it can be changed into another prime (2162034702473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1081017351216 + 1081017351217.

It is an arithmetic number, because the mean of its divisors is an integer number (1081017351217).

Almost surely, 22162034702433 is an apocalyptic number.

It is an amenable number.

2162034702433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2162034702433 is an equidigital number, since it uses as much as digits as its factorization.

2162034702433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 37.

The spelling of 2162034702433 in words is "two trillion, one hundred sixty-two billion, thirty-four million, seven hundred two thousand, four hundred thirty-three".