Base | Representation |
---|---|
bin | 1100100110111111001… |
… | …1111100000010110001 |
3 | 202201010220202010202112 |
4 | 3021233303330002301 |
5 | 12022121302013212 |
6 | 243303225255105 |
7 | 21436102516154 |
oct | 3115763740261 |
9 | 681126663675 |
10 | 216624251057 |
11 | 83962819065 |
12 | 35b97034495 |
13 | 17573512316 |
14 | a6add0dc9b |
15 | 597cb78422 |
hex | 326fcfc0b1 |
216624251057 has 2 divisors, whose sum is σ = 216624251058. Its totient is φ = 216624251056.
The previous prime is 216624251023. The next prime is 216624251111. The reversal of 216624251057 is 750152426612.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 118632713761 + 97991537296 = 344431^2 + 313036^2 .
It is a cyclic number.
It is not a de Polignac number, because 216624251057 - 212 = 216624246961 is a prime.
It is a super-2 number, since 2×2166242510572 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (216624251957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 108312125528 + 108312125529.
It is an arithmetic number, because the mean of its divisors is an integer number (108312125529).
Almost surely, 2216624251057 is an apocalyptic number.
It is an amenable number.
216624251057 is a deficient number, since it is larger than the sum of its proper divisors (1).
216624251057 is an equidigital number, since it uses as much as digits as its factorization.
216624251057 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 41.
Adding to 216624251057 its reverse (750152426612), we get a palindrome (966776677669).
The spelling of 216624251057 in words is "two hundred sixteen billion, six hundred twenty-four million, two hundred fifty-one thousand, fifty-seven".
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