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2166885590113 is a prime number
BaseRepresentation
bin11111100010000100011…
…100100010010001100001
321200011002222112012220001
4133202010130202101201
5241000240202340423
64335241542220001
7312360305421016
oct37420434422141
97604088465801
102166885590113
11765a75474792
122abb59724601
1312944b1b956a
1476c40a5b70d
153b5741d4cad
hex1f884722461

2166885590113 has 2 divisors, whose sum is σ = 2166885590114. Its totient is φ = 2166885590112.

The previous prime is 2166885590099. The next prime is 2166885590137. The reversal of 2166885590113 is 3110955886612.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1885659015249 + 281226574864 = 1373193^2 + 530308^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2166885590113 is a prime.

It is not a weakly prime, because it can be changed into another prime (2166885590143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1083442795056 + 1083442795057.

It is an arithmetic number, because the mean of its divisors is an integer number (1083442795057).

Almost surely, 22166885590113 is an apocalyptic number.

It is an amenable number.

2166885590113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2166885590113 is an equidigital number, since it uses as much as digits as its factorization.

2166885590113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3110400, while the sum is 55.

The spelling of 2166885590113 in words is "two trillion, one hundred sixty-six billion, eight hundred eighty-five million, five hundred ninety thousand, one hundred thirteen".