Base | Representation |
---|---|
bin | 11111100110111101001… |
… | …101011011110010011111 |
3 | 21200122122200021011211122 |
4 | 133212331031123302133 |
5 | 241042012010244444 |
6 | 4341510350241155 |
7 | 312634323004406 |
oct | 37467515336237 |
9 | 7618580234748 |
10 | 2172132899999 |
11 | 768218438327 |
12 | 2b0b82ab61bb |
13 | 129aa635825a |
14 | 771bb8d863d |
15 | 3b77ebdd4ee |
hex | 1f9bd35bc9f |
2172132899999 has 4 divisors (see below), whose sum is σ = 2218348493664. Its totient is φ = 2125917306336.
The previous prime is 2172132899983. The next prime is 2172132900097. The reversal of 2172132899999 is 9999982312712.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2172132899999 - 24 = 2172132899983 is a prime.
It is a super-2 number, since 2×21721328999992 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2172132899939) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23107796762 + ... + 23107796855.
It is an arithmetic number, because the mean of its divisors is an integer number (554587123416).
Almost surely, 22172132899999 is an apocalyptic number.
2172132899999 is a deficient number, since it is larger than the sum of its proper divisors (46215593665).
2172132899999 is an equidigital number, since it uses as much as digits as its factorization.
2172132899999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46215593664.
The product of its digits is 79361856, while the sum is 71.
The spelling of 2172132899999 in words is "two trillion, one hundred seventy-two billion, one hundred thirty-two million, eight hundred ninety-nine thousand, nine hundred ninety-nine".
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