Base | Representation |
---|---|
bin | 11111100111100101110… |
… | …001000000000000000001 |
3 | 21200201102002120200122011 |
4 | 133213211301000000001 |
5 | 241044410201441001 |
6 | 4342102054012521 |
7 | 312660224264023 |
oct | 37474561000001 |
9 | 7621362520564 |
10 | 2172813312001 |
11 | 7685375189a2 |
12 | 2b1132947141 |
13 | 129b842c98c7 |
14 | 77244014013 |
15 | 3b7be7e1d51 |
hex | 1f9e5c40001 |
2172813312001 has 2 divisors, whose sum is σ = 2172813312002. Its totient is φ = 2172813312000.
The previous prime is 2172813311993. The next prime is 2172813312053. The reversal of 2172813312001 is 1002133182712.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1799246649600 + 373566662401 = 1341360^2 + 611201^2 .
It is a cyclic number.
It is not a de Polignac number, because 2172813312001 - 23 = 2172813311993 is a prime.
It is a super-2 number, since 2×21728133120012 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2172813312401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1086406656000 + 1086406656001.
It is an arithmetic number, because the mean of its divisors is an integer number (1086406656001).
Almost surely, 22172813312001 is an apocalyptic number.
It is an amenable number.
2172813312001 is a deficient number, since it is larger than the sum of its proper divisors (1).
2172813312001 is an equidigital number, since it uses as much as digits as its factorization.
2172813312001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 2172813312001 its reverse (1002133182712), we get a palindrome (3174946494713).
The spelling of 2172813312001 in words is "two trillion, one hundred seventy-two billion, eight hundred thirteen million, three hundred twelve thousand, one".
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