Base | Representation |
---|---|
bin | 1010000000010010101000… |
… | …00001001111000001101011 |
3 | 2212220012110000001020220011 |
4 | 11000021110001033001223 |
5 | 10340422433404144242 |
6 | 114442433405512351 |
7 | 4430315155240123 |
oct | 500112401170153 |
9 | 85805400036804 |
10 | 22000232099947 |
11 | 7012278525a62 |
12 | 25739612726b7 |
13 | c377c796114a |
14 | 560b61887c83 |
15 | 28242340dd17 |
hex | 14025404f06b |
22000232099947 has 2 divisors, whose sum is σ = 22000232099948. Its totient is φ = 22000232099946.
The previous prime is 22000232099939. The next prime is 22000232100013. The reversal of 22000232099947 is 74999023200022.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 22000232099947 - 23 = 22000232099939 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 22000232099947.
It is not a weakly prime, because it can be changed into another prime (22000232069947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000116049973 + 11000116049974.
It is an arithmetic number, because the mean of its divisors is an integer number (11000116049974).
Almost surely, 222000232099947 is an apocalyptic number.
22000232099947 is a deficient number, since it is larger than the sum of its proper divisors (1).
22000232099947 is an equidigital number, since it uses as much as digits as its factorization.
22000232099947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 49.
Adding to 22000232099947 its reverse (74999023200022), we get a palindrome (96999255299969).
The spelling of 22000232099947 in words is "twenty-two trillion, two hundred thirty-two million, ninety-nine thousand, nine hundred forty-seven".
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