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22000411313 is a prime number
BaseRepresentation
bin10100011111010100…
…111010001010110001
32002210020122200200122
4110133110322022301
5330024101130223
614035025100025
71406122260566
oct243724721261
962706580618
1022000411313
11936a727711
12431ba87615
1320c7c6727a
1410c9c4a86d
1588b6b05c8
hex51f53a2b1

22000411313 has 2 divisors, whose sum is σ = 22000411314. Its totient is φ = 22000411312.

The previous prime is 22000411309. The next prime is 22000411327. The reversal of 22000411313 is 31311400022.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16809641104 + 5190770209 = 129652^2 + 72047^2 .

It is a cyclic number.

It is not a de Polignac number, because 22000411313 - 22 = 22000411309 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 22000411291 and 22000411300.

It is not a weakly prime, because it can be changed into another prime (22000411333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000205656 + 11000205657.

It is an arithmetic number, because the mean of its divisors is an integer number (11000205657).

Almost surely, 222000411313 is an apocalyptic number.

It is an amenable number.

22000411313 is a deficient number, since it is larger than the sum of its proper divisors (1).

22000411313 is an equidigital number, since it uses as much as digits as its factorization.

22000411313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 22000411313 its reverse (31311400022), we get a palindrome (53311811335).

The spelling of 22000411313 in words is "twenty-two billion, four hundred eleven thousand, three hundred thirteen".