Base | Representation |
---|---|
bin | 10100011111010100… |
… | …111010001010110001 |
3 | 2002210020122200200122 |
4 | 110133110322022301 |
5 | 330024101130223 |
6 | 14035025100025 |
7 | 1406122260566 |
oct | 243724721261 |
9 | 62706580618 |
10 | 22000411313 |
11 | 936a727711 |
12 | 431ba87615 |
13 | 20c7c6727a |
14 | 10c9c4a86d |
15 | 88b6b05c8 |
hex | 51f53a2b1 |
22000411313 has 2 divisors, whose sum is σ = 22000411314. Its totient is φ = 22000411312.
The previous prime is 22000411309. The next prime is 22000411327. The reversal of 22000411313 is 31311400022.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16809641104 + 5190770209 = 129652^2 + 72047^2 .
It is a cyclic number.
It is not a de Polignac number, because 22000411313 - 22 = 22000411309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22000411291 and 22000411300.
It is not a weakly prime, because it can be changed into another prime (22000411333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11000205656 + 11000205657.
It is an arithmetic number, because the mean of its divisors is an integer number (11000205657).
Almost surely, 222000411313 is an apocalyptic number.
It is an amenable number.
22000411313 is a deficient number, since it is larger than the sum of its proper divisors (1).
22000411313 is an equidigital number, since it uses as much as digits as its factorization.
22000411313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 22000411313 its reverse (31311400022), we get a palindrome (53311811335).
The spelling of 22000411313 in words is "twenty-two billion, four hundred eleven thousand, three hundred thirteen".
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