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2200312102433 is a prime number
BaseRepresentation
bin100000000001001100110…
…100100011111000100001
321210100101112101222111212
4200001030310203320201
5242022214344234213
64402450500315505
7314652533165504
oct40011464437041
97710345358455
102200312102433
11779168902185
122b65280a2b95
1312c64742ab33
14786d21b513b
153c37da519a8
hex2004cd23e21

2200312102433 has 2 divisors, whose sum is σ = 2200312102434. Its totient is φ = 2200312102432.

The previous prime is 2200312102349. The next prime is 2200312102459. The reversal of 2200312102433 is 3342012130022.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2195206714129 + 5105388304 = 1481623^2 + 71452^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2200312102433 is a prime.

It is a super-2 number, since 2×22003121024332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2200312102399 and 2200312102408.

It is not a weakly prime, because it can be changed into another prime (2200312152433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1100156051216 + 1100156051217.

It is an arithmetic number, because the mean of its divisors is an integer number (1100156051217).

Almost surely, 22200312102433 is an apocalyptic number.

It is an amenable number.

2200312102433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2200312102433 is an equidigital number, since it uses as much as digits as its factorization.

2200312102433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 2200312102433 its reverse (3342012130022), we get a palindrome (5542324232455).

The spelling of 2200312102433 in words is "two trillion, two hundred billion, three hundred twelve million, one hundred two thousand, four hundred thirty-three".