Base | Representation |
---|---|
bin | 100000000001001110100… |
… | …000001011000001001111 |
3 | 21210100110111111011221221 |
4 | 200001032200023001033 |
5 | 242022244104442033 |
6 | 4402453345104211 |
7 | 314653325026531 |
oct | 40011640130117 |
9 | 7710414434857 |
10 | 2200340312143 |
11 | 77918281a596 |
12 | 2b6535628067 |
13 | 12c650226c7c |
14 | 786d5c39851 |
15 | 3c38127512d |
hex | 2004e80b04f |
2200340312143 has 4 divisors (see below), whose sum is σ = 2276214116040. Its totient is φ = 2124466508248.
The previous prime is 2200340312099. The next prime is 2200340312147. The reversal of 2200340312143 is 3412130430022.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2200340312143 - 217 = 2200340181071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2200340312147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37936901905 + ... + 37936901962.
It is an arithmetic number, because the mean of its divisors is an integer number (569053529010).
Almost surely, 22200340312143 is an apocalyptic number.
2200340312143 is a deficient number, since it is larger than the sum of its proper divisors (75873803897).
2200340312143 is an equidigital number, since it uses as much as digits as its factorization.
2200340312143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 75873803896.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 2200340312143 its reverse (3412130430022), we get a palindrome (5612470742165).
The spelling of 2200340312143 in words is "two trillion, two hundred billion, three hundred forty million, three hundred twelve thousand, one hundred forty-three".
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