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2201354364142 = 21100677182071
BaseRepresentation
bin100000000010001010111…
…100011110010011101110
321210110002011121100210101
4200002022330132103232
5242031333204123032
64403142131501314
7315020420234413
oct40021274362356
97713064540711
102201354364142
1177965317089a
122b677915783a
1312c78234413b
14787907a410a
153c3e02cede7
hex2008af1e4ee

2201354364142 has 4 divisors (see below), whose sum is σ = 3302031546216. Its totient is φ = 1100677182070.

The previous prime is 2201354364127. The next prime is 2201354364149. The reversal of 2201354364142 is 2414634531022.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×22013543641422 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2201354364149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550338591034 + ... + 550338591037.

It is an arithmetic number, because the mean of its divisors is an integer number (825507886554).

Almost surely, 22201354364142 is an apocalyptic number.

2201354364142 is a deficient number, since it is larger than the sum of its proper divisors (1100677182074).

2201354364142 is a wasteful number, since it uses less digits than its factorization.

2201354364142 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1100677182073.

The product of its (nonzero) digits is 138240, while the sum is 37.

Adding to 2201354364142 its reverse (2414634531022), we get a palindrome (4615988895164).

The spelling of 2201354364142 in words is "two trillion, two hundred one billion, three hundred fifty-four million, three hundred sixty-four thousand, one hundred forty-two".

Divisors: 1 2 1100677182071 2201354364142