Search a number
-
+
2202123133 = 7314589019
BaseRepresentation
bin1000001101000001…
…1011101101111101
312200110200110001001
42003100123231331
514002220420013
61002303050301
7105366511030
oct20320335575
95613613031
102202123133
11a3004a781
125155a0991
132912c5b52
1416c671017
15cd4daddd
hex8341bb7d

2202123133 has 4 divisors (see below), whose sum is σ = 2516712160. Its totient is φ = 1887534108.

The previous prime is 2202123073. The next prime is 2202123167. The reversal of 2202123133 is 3313212022.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3313212022 = 21656606011.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2202123133 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 2202123133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2202523133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157294503 + ... + 157294516.

It is an arithmetic number, because the mean of its divisors is an integer number (629178040).

Almost surely, 22202123133 is an apocalyptic number.

It is an amenable number.

2202123133 is a deficient number, since it is larger than the sum of its proper divisors (314589027).

2202123133 is an equidigital number, since it uses as much as digits as its factorization.

2202123133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 314589026.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 2202123133 is about 46926.7848142188. The cubic root of 2202123133 is about 1301.0096954595.

Adding to 2202123133 its reverse (3313212022), we get a palindrome (5515335155).

Subtracting 2202123133 from its reverse (3313212022), we obtain a square (1111088889 = 333332).

It can be divided in two parts, 2202123 and 133, that added together give a square (2202256 = 14842).

The spelling of 2202123133 in words is "two billion, two hundred two million, one hundred twenty-three thousand, one hundred thirty-three".

Divisors: 1 7 314589019 2202123133