Base | Representation |
---|---|
bin | 100000001010010100111… |
… | …100101101000000101001 |
3 | 21211021200111220000120001 |
4 | 200022110330231000221 |
5 | 242202302201143423 |
6 | 4411151141103001 |
7 | 315450432102625 |
oct | 40122474550051 |
9 | 7737614800501 |
10 | 2210112131113 |
11 | 782337753837 |
12 | 2b84020b7a61 |
13 | 130549871083 |
14 | 78d81962185 |
15 | 3c7540adcad |
hex | 20294f2d029 |
2210112131113 has 2 divisors, whose sum is σ = 2210112131114. Its totient is φ = 2210112131112.
The previous prime is 2210112131039. The next prime is 2210112131131. The reversal of 2210112131113 is 3111312110122.
Together with next prime (2210112131131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1942670077209 + 267442053904 = 1393797^2 + 517148^2 .
It is a cyclic number.
It is not a de Polignac number, because 2210112131113 - 233 = 2201522196521 is a prime.
It is not a weakly prime, because it can be changed into another prime (2210112131713) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1105056065556 + 1105056065557.
It is an arithmetic number, because the mean of its divisors is an integer number (1105056065557).
Almost surely, 22210112131113 is an apocalyptic number.
It is an amenable number.
2210112131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2210112131113 is an equidigital number, since it uses as much as digits as its factorization.
2210112131113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 2210112131113 its reverse (3111312110122), we get a palindrome (5321424241235).
The spelling of 2210112131113 in words is "two trillion, two hundred ten billion, one hundred twelve million, one hundred thirty-one thousand, one hundred thirteen".
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