Base | Representation |
---|---|
bin | 110010010000001010101100… |
… | …000100100101110011100011 |
3 | 1001222112122222212011101010211 |
4 | 302100022230010211303203 |
5 | 212432040231341032042 |
6 | 2102020040443234551 |
7 | 64360453645261312 |
oct | 6220125404456343 |
9 | 1058478885141124 |
10 | 221013314002147 |
11 | 64470246a49137 |
12 | 20955a3b818a57 |
13 | 9642609ca1314 |
14 | 3c8115c630279 |
15 | 1a840e4466017 |
hex | c902ac125ce3 |
221013314002147 has 2 divisors, whose sum is σ = 221013314002148. Its totient is φ = 221013314002146.
The previous prime is 221013314002109. The next prime is 221013314002163. The reversal of 221013314002147 is 741200413310122.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 221013314002147 - 211 = 221013314000099 is a prime.
It is not a weakly prime, because it can be changed into another prime (221013314012147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110506657001073 + 110506657001074.
It is an arithmetic number, because the mean of its divisors is an integer number (110506657001074).
Almost surely, 2221013314002147 is an apocalyptic number.
221013314002147 is a deficient number, since it is larger than the sum of its proper divisors (1).
221013314002147 is an equidigital number, since it uses as much as digits as its factorization.
221013314002147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 221013314002147 its reverse (741200413310122), we get a palindrome (962213727312269).
The spelling of 221013314002147 in words is "two hundred twenty-one trillion, thirteen billion, three hundred fourteen million, two thousand, one hundred forty-seven".
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