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221022012113 = 731574573159
BaseRepresentation
bin1100110111010111110…
…0000100001011010001
3210010111101220112210122
43031311330010023101
512110123113341423
6245311444440025
721653063051030
oct3156574041321
9703441815718
10221022012113
118580a189031
1236a039a9015
1317ac46701b6
14a9aa004717
155b38cbd8c8
hex3375f042d1

221022012113 has 4 divisors (see below), whose sum is σ = 252596585280. Its totient is φ = 189447438948.

The previous prime is 221022012089. The next prime is 221022012173. The reversal of 221022012113 is 311210220122.

221022012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311210220122 = 2155605110061.

It is a cyclic number.

It is not a de Polignac number, because 221022012113 - 212 = 221022008017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 221022012091 and 221022012100.

It is not an unprimeable number, because it can be changed into a prime (221022012173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15787286573 + ... + 15787286586.

It is an arithmetic number, because the mean of its divisors is an integer number (63149146320).

Almost surely, 2221022012113 is an apocalyptic number.

It is an amenable number.

221022012113 is a deficient number, since it is larger than the sum of its proper divisors (31574573167).

221022012113 is an equidigital number, since it uses as much as digits as its factorization.

221022012113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31574573166.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 221022012113 its reverse (311210220122), we get a palindrome (532232232235).

The spelling of 221022012113 in words is "two hundred twenty-one billion, twenty-two million, twelve thousand, one hundred thirteen".

Divisors: 1 7 31574573159 221022012113