Base | Representation |
---|---|
bin | 100000001011010001110… |
… | …000010110000001101111 |
3 | 21211101022121112001010121 |
4 | 200023101300112001233 |
5 | 242211344332121143 |
6 | 4411440302545411 |
7 | 315514630312243 |
oct | 40132160260157 |
9 | 7741277461117 |
10 | 2211132301423 |
11 | 7828105a38a1 |
12 | 2b8647898267 |
13 | 130680021046 |
14 | 7903b240423 |
15 | 3c7b39267ed |
hex | 202d1c1606f |
2211132301423 has 4 divisors (see below), whose sum is σ = 2282459149888. Its totient is φ = 2139805452960.
The previous prime is 2211132301421. The next prime is 2211132301451. The reversal of 2211132301423 is 3241032311122.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2211132301423 - 21 = 2211132301421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2211132301421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35663424186 + ... + 35663424247.
It is an arithmetic number, because the mean of its divisors is an integer number (570614787472).
Almost surely, 22211132301423 is an apocalyptic number.
2211132301423 is a deficient number, since it is larger than the sum of its proper divisors (71326848465).
2211132301423 is an equidigital number, since it uses as much as digits as its factorization.
2211132301423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71326848464.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2211132301423 its reverse (3241032311122), we get a palindrome (5452164612545).
The spelling of 2211132301423 in words is "two trillion, two hundred eleven billion, one hundred thirty-two million, three hundred one thousand, four hundred twenty-three".
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