Base | Representation |
---|---|
bin | 110010010001101111000101… |
… | …111011111011000101110011 |
3 | 1001222220222021012011012112112 |
4 | 302101233011323323011303 |
5 | 212440322024230320201 |
6 | 2102141350253315535 |
7 | 64401321353203046 |
oct | 6221570573730563 |
9 | 1058828235135475 |
10 | 221121122120051 |
11 | 64501a3990383a |
12 | 20972908495bab |
13 | 964c82b34c86a |
14 | 3c8646868ac5d |
15 | 1a86d03de70bb |
hex | c91bc5efb173 |
221121122120051 has 2 divisors, whose sum is σ = 221121122120052. Its totient is φ = 221121122120050.
The previous prime is 221121122120033. The next prime is 221121122120113. The reversal of 221121122120051 is 150021221121122.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-221121122120051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 221121122119999 and 221121122120026.
It is not a weakly prime, because it can be changed into another prime (221126122120051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110560561060025 + 110560561060026.
It is an arithmetic number, because the mean of its divisors is an integer number (110560561060026).
Almost surely, 2221121122120051 is an apocalyptic number.
221121122120051 is a deficient number, since it is larger than the sum of its proper divisors (1).
221121122120051 is an equidigital number, since it uses as much as digits as its factorization.
221121122120051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 320, while the sum is 23.
Adding to 221121122120051 its reverse (150021221121122), we get a palindrome (371142343241173).
The spelling of 221121122120051 in words is "two hundred twenty-one trillion, one hundred twenty-one billion, one hundred twenty-two million, one hundred twenty thousand, fifty-one".
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