Base | Representation |
---|---|
bin | 1100110111110001101… |
… | …1111111001001100111 |
3 | 210010210000001220122121 |
4 | 3031330123333021213 |
5 | 12110334021342211 |
6 | 245330341410411 |
7 | 21655555566424 |
oct | 3157433771147 |
9 | 703700056577 |
10 | 221131043431 |
11 | 85865788961 |
12 | 36a34409a07 |
13 | 17b1112667c |
14 | a9ba6a6d4b |
15 | 5b43659271 |
hex | 337c6ff267 |
221131043431 has 4 divisors (see below), whose sum is σ = 221132275864. Its totient is φ = 221129811000.
The previous prime is 221131043407. The next prime is 221131043443. The reversal of 221131043431 is 134340131122.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 221131043431 - 221 = 221128946279 is a prime.
It is a super-2 number, since 2×2211310434312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 221131043396 and 221131043405.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (221131043461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289245 + ... + 725206.
It is an arithmetic number, because the mean of its divisors is an integer number (55283068966).
Almost surely, 2221131043431 is an apocalyptic number.
221131043431 is a deficient number, since it is larger than the sum of its proper divisors (1232433).
221131043431 is a wasteful number, since it uses less digits than its factorization.
221131043431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1232432.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 221131043431 its reverse (134340131122), we get a palindrome (355471174553).
The spelling of 221131043431 in words is "two hundred twenty-one billion, one hundred thirty-one million, forty-three thousand, four hundred thirty-one".
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