Base | Representation |
---|---|
bin | 10100100110000011… |
… | …010100100111000001 |
3 | 2010002002222001122211 |
4 | 110212003110213001 |
5 | 330241442212122 |
6 | 14054135302121 |
7 | 1411662310642 |
oct | 244603244701 |
9 | 63062861584 |
10 | 22113241537 |
11 | 9418391732 |
12 | 435181a941 |
13 | 211545090a |
14 | 10dac1b6c9 |
15 | 89654b877 |
hex | 5260d49c1 |
22113241537 has 2 divisors, whose sum is σ = 22113241538. Its totient is φ = 22113241536.
The previous prime is 22113241519. The next prime is 22113241567. The reversal of 22113241537 is 73514231122.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20480758321 + 1632483216 = 143111^2 + 40404^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-22113241537 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22113241499 and 22113241508.
It is not a weakly prime, because it can be changed into another prime (22113241517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11056620768 + 11056620769.
It is an arithmetic number, because the mean of its divisors is an integer number (11056620769).
Almost surely, 222113241537 is an apocalyptic number.
It is an amenable number.
22113241537 is a deficient number, since it is larger than the sum of its proper divisors (1).
22113241537 is an equidigital number, since it uses as much as digits as its factorization.
22113241537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10080, while the sum is 31.
Adding to 22113241537 its reverse (73514231122), we get a palindrome (95627472659).
The spelling of 22113241537 in words is "twenty-two billion, one hundred thirteen million, two hundred forty-one thousand, five hundred thirty-seven".
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