2212001113 has 4 divisors (see below), whose sum is σ = 2528001280. Its totient is φ = 1896000948.

The previous prime is 2212001107. The next prime is 2212001119. The reversal of 2212001113 is 3111002122.

2212001113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3111002122 = 2 ⋅1555501061.

It is an interprime number because it is at equal distance from previous prime (2212001107) and next prime (2212001119).

It is a cyclic number.

It is not a de Polignac number, because 2212001113 - 2¹³ = 2211992921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2212001093 and 2212001102.

It is not an unprimeable number, because it can be changed into a prime (2212001119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 158000073 + ... + 158000086.

It is an arithmetic number, because the mean of its divisors is an integer number (632000320).

Almost surely, 2^2212001113 is an apocalyptic number.

It is an amenable number.

2212001113 is a deficient number, since it is larger than the sum of its proper divisors (316000167).

2212001113 is an equidigital number, since it uses as much as digits as its factorization.

2212001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 316000166.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 2212001113 is about 47031.9158976115. The cubic root of 2212001113 is about 1302.9520906116.

Adding to 2212001113 its reverse (3111002122), we get a palindrome (5323003235).

The spelling of 2212001113 in words is "two billion, two hundred twelve million, one thousand, one hundred thirteen".