Base | Representation |
---|---|
bin | 110010010011000001111110… |
… | …101100100001000011110011 |
3 | 1002000020110222200122112010202 |
4 | 302103001332230201003303 |
5 | 212443301312012242042 |
6 | 2102250305440545415 |
7 | 64410622010044544 |
oct | 6223017654410363 |
9 | 1060213880575122 |
10 | 221210121212147 |
11 | 6453675a540a11 |
12 | 2098800602226b |
13 | 96580429a7632 |
14 | 3c8a8ac6824cb |
15 | 1a892b2463632 |
hex | c9307eb210f3 |
221210121212147 has 2 divisors, whose sum is σ = 221210121212148. Its totient is φ = 221210121212146.
The previous prime is 221210121212141. The next prime is 221210121212209. The reversal of 221210121212147 is 741212121012122.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 221210121212147 - 228 = 221209852776691 is a prime.
It is not a weakly prime, because it can be changed into another prime (221210121212141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110605060606073 + 110605060606074.
It is an arithmetic number, because the mean of its divisors is an integer number (110605060606074).
Almost surely, 2221210121212147 is an apocalyptic number.
221210121212147 is a deficient number, since it is larger than the sum of its proper divisors (1).
221210121212147 is an equidigital number, since it uses as much as digits as its factorization.
221210121212147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1792, while the sum is 29.
Adding to 221210121212147 its reverse (741212121012122), we get a palindrome (962422242224269).
The spelling of 221210121212147 in words is "two hundred twenty-one trillion, two hundred ten billion, one hundred twenty-one million, two hundred twelve thousand, one hundred forty-seven".
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