Base | Representation |
---|---|
bin | 10100100110100001… |
… | …010011111100001001 |
3 | 2010002122202110201022 |
4 | 110212201103330021 |
5 | 330301000244423 |
6 | 14055020002225 |
7 | 1412116162664 |
oct | 244641237411 |
9 | 63078673638 |
10 | 22121103113 |
11 | 94218711aa |
12 | 4354390375 |
13 | 2116c74035 |
14 | 10dbca66db |
15 | 8970a0dc8 |
hex | 526853f09 |
22121103113 has 2 divisors, whose sum is σ = 22121103114. Its totient is φ = 22121103112.
The previous prime is 22121103089. The next prime is 22121103127. The reversal of 22121103113 is 31130112122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12492979984 + 9628123129 = 111772^2 + 98123^2 .
It is a cyclic number.
It is not a de Polignac number, because 22121103113 - 224 = 22104325897 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22121103091 and 22121103100.
It is not a weakly prime, because it can be changed into another prime (22121103313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11060551556 + 11060551557.
It is an arithmetic number, because the mean of its divisors is an integer number (11060551557).
Almost surely, 222121103113 is an apocalyptic number.
It is an amenable number.
22121103113 is a deficient number, since it is larger than the sum of its proper divisors (1).
22121103113 is an equidigital number, since it uses as much as digits as its factorization.
22121103113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 22121103113 its reverse (31130112122), we get a palindrome (53251215235).
Subtracting 22121103113 from its reverse (31130112122), we obtain a palindrome (9009009009).
The spelling of 22121103113 in words is "twenty-two billion, one hundred twenty-one million, one hundred three thousand, one hundred thirteen".
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