Base | Representation |
---|---|
bin | 100000001100001100101… |
… | …101000101000001111001 |
3 | 21211110212112111102122202 |
4 | 200030030231011001321 |
5 | 242220411023113423 |
6 | 4412122352355545 |
7 | 315551266546253 |
oct | 40141455050171 |
9 | 7743775442582 |
10 | 2212121301113 |
11 | 783178893a09 |
12 | 2b8882b45bb5 |
13 | 1307a9ba9269 |
14 | 790d2726cd3 |
15 | 3c820683728 |
hex | 2030cb45079 |
2212121301113 has 2 divisors, whose sum is σ = 2212121301114. Its totient is φ = 2212121301112.
The previous prime is 2212121301031. The next prime is 2212121301151. The reversal of 2212121301113 is 3111031212122.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2007285403369 + 204835897744 = 1416787^2 + 452588^2 .
It is a cyclic number.
It is not a de Polignac number, because 2212121301113 - 212 = 2212121297017 is a prime.
It is not a weakly prime, because it can be changed into another prime (2212121301163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106060650556 + 1106060650557.
It is an arithmetic number, because the mean of its divisors is an integer number (1106060650557).
Almost surely, 22212121301113 is an apocalyptic number.
It is an amenable number.
2212121301113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2212121301113 is an equidigital number, since it uses as much as digits as its factorization.
2212121301113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 2212121301113 its reverse (3111031212122), we get a palindrome (5323152513235).
The spelling of 2212121301113 in words is "two trillion, two hundred twelve billion, one hundred twenty-one million, three hundred one thousand, one hundred thirteen".
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