Base | Representation |
---|---|
bin | 100000001100011111010… |
… | …011010001100111011111 |
3 | 21211111200021120211012101 |
4 | 200030133103101213133 |
5 | 242222030411212111 |
6 | 4412213335545531 |
7 | 315562105536616 |
oct | 40143723214737 |
9 | 7744607524171 |
10 | 2212433304031 |
11 | 783318a16365 |
12 | 2b894b52b2a7 |
13 | 13082971a482 |
14 | 79121d4287d |
15 | 3c83cc63bc1 |
hex | 2031f4d19df |
2212433304031 has 4 divisors (see below), whose sum is σ = 2212485530152. Its totient is φ = 2212381077912.
The previous prime is 2212433304001. The next prime is 2212433304083. The reversal of 2212433304031 is 1304033342122.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2212433304031 - 27 = 2212433303903 is a prime.
It is a super-2 number, since 2×22124333040312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2212433304001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26049465 + ... + 26134258.
It is an arithmetic number, because the mean of its divisors is an integer number (553121382538).
Almost surely, 22212433304031 is an apocalyptic number.
2212433304031 is a deficient number, since it is larger than the sum of its proper divisors (52226121).
2212433304031 is an equidigital number, since it uses as much as digits as its factorization.
2212433304031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52226120.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 2212433304031 its reverse (1304033342122), we get a palindrome (3516466646153).
The spelling of 2212433304031 in words is "two trillion, two hundred twelve billion, four hundred thirty-three million, three hundred four thousand, thirty-one".
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