Base | Representation |
---|---|
bin | 100000001100011111010… |
… | …111000101110000110011 |
3 | 21211111200100110121222011 |
4 | 200030133113011300303 |
5 | 242222031140212201 |
6 | 4412213413223351 |
7 | 315562120203256 |
oct | 40143727056063 |
9 | 7744610417864 |
10 | 2212434304051 |
11 | 783319539724 |
12 | 2b894b931b57 |
13 | 1308299aa6ba |
14 | 7912212309d |
15 | 3c83cdb0151 |
hex | 2031f5c5c33 |
2212434304051 has 2 divisors, whose sum is σ = 2212434304052. Its totient is φ = 2212434304050.
The previous prime is 2212434304033. The next prime is 2212434304057. The reversal of 2212434304051 is 1504034342122.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2212434304051 - 25 = 2212434304019 is a prime.
It is not a weakly prime, because it can be changed into another prime (2212434304057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106217152025 + 1106217152026.
It is an arithmetic number, because the mean of its divisors is an integer number (1106217152026).
Almost surely, 22212434304051 is an apocalyptic number.
2212434304051 is a deficient number, since it is larger than the sum of its proper divisors (1).
2212434304051 is an equidigital number, since it uses as much as digits as its factorization.
2212434304051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 2212434304051 its reverse (1504034342122), we get a palindrome (3716468646173).
The spelling of 2212434304051 in words is "two trillion, two hundred twelve billion, four hundred thirty-four million, three hundred four thousand, fifty-one".
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