Base | Representation |
---|---|
bin | 100000001100100100000… |
… | …010110101011101101101 |
3 | 21211111212211022201120202 |
4 | 200030210002311131231 |
5 | 242222211244133433 |
6 | 4412225301323245 |
7 | 315564063120146 |
oct | 40144402653555 |
9 | 7744784281522 |
10 | 2212512880493 |
11 | 783359928333 |
12 | 2b8972106525 |
13 | 13084005cb36 |
14 | 7912c738acd |
15 | 3c844c31ee8 |
hex | 203240b576d |
2212512880493 has 4 divisors (see below), whose sum is σ = 2213753775648. Its totient is φ = 2211271985340.
The previous prime is 2212512880447. The next prime is 2212512880507. The reversal of 2212512880493 is 3940882152122.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 2212512880493 - 216 = 2212512814957 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2212512880093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 620444903 + ... + 620448468.
It is an arithmetic number, because the mean of its divisors is an integer number (553438443912).
Almost surely, 22212512880493 is an apocalyptic number.
It is an amenable number.
2212512880493 is a deficient number, since it is larger than the sum of its proper divisors (1240895155).
2212512880493 is a wasteful number, since it uses less digits than its factorization.
2212512880493 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1240895154.
The product of its (nonzero) digits is 552960, while the sum is 47.
The spelling of 2212512880493 in words is "two trillion, two hundred twelve billion, five hundred twelve million, eight hundred eighty thousand, four hundred ninety-three".
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