Base | Representation |
---|---|
bin | 1010000100000100011010… |
… | …10111000110111001110011 |
3 | 2220100121111202110001110020 |
4 | 11002002031113012321303 |
5 | 10400034312021412120 |
6 | 115022222415134523 |
7 | 4442562046056555 |
oct | 502021527067163 |
9 | 86317452401406 |
10 | 22130043154035 |
11 | 7062331482243 |
12 | 2594b4a814443 |
13 | c46b1464bc5b |
14 | 567157c0b4d5 |
15 | 2859be89d640 |
hex | 14208d5c6e73 |
22130043154035 has 32 divisors (see below), whose sum is σ = 37584390318912. Its totient is φ = 11080711987200.
The previous prime is 22130043154013. The next prime is 22130043154057. The reversal of 22130043154035 is 53045134003122.
It is an interprime number because it is at equal distance from previous prime (22130043154013) and next prime (22130043154057).
It is not a de Polignac number, because 22130043154035 - 215 = 22130043121267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 22130043153987 and 22130043154005.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 108107824 + ... + 108312333.
It is an arithmetic number, because the mean of its divisors is an integer number (1174512197466).
Almost surely, 222130043154035 is an apocalyptic number.
22130043154035 is a deficient number, since it is larger than the sum of its proper divisors (15454347164877).
22130043154035 is a wasteful number, since it uses less digits than its factorization.
22130043154035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 216420583.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 22130043154035 its reverse (53045134003122), we get a palindrome (75175177157157).
The spelling of 22130043154035 in words is "twenty-two trillion, one hundred thirty billion, forty-three million, one hundred fifty-four thousand, thirty-five".
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