Base | Representation |
---|---|
bin | 100000001101000010100… |
… | …010101101000011101011 |
3 | 21211120012111010021202201 |
4 | 200031002202231003223 |
5 | 242224233241114042 |
6 | 4412352140241031 |
7 | 315612545212264 |
oct | 40150242550353 |
9 | 7746174107681 |
10 | 2213024551147 |
11 | 7835a1736043 |
12 | 2b8a95540177 |
13 | 1308c2070037 |
14 | 7917a68b96b |
15 | 3c874b031b7 |
hex | 203428ad0eb |
2213024551147 has 2 divisors, whose sum is σ = 2213024551148. Its totient is φ = 2213024551146.
The previous prime is 2213024551099. The next prime is 2213024551249. The reversal of 2213024551147 is 7411554203122.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2213024551147 - 215 = 2213024518379 is a prime.
It is not a weakly prime, because it can be changed into another prime (2213024551747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106512275573 + 1106512275574.
It is an arithmetic number, because the mean of its divisors is an integer number (1106512275574).
Almost surely, 22213024551147 is an apocalyptic number.
2213024551147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2213024551147 is an equidigital number, since it uses as much as digits as its factorization.
2213024551147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 37.
Adding to 2213024551147 its reverse (7411554203122), we get a palindrome (9624578754269).
The spelling of 2213024551147 in words is "two trillion, two hundred thirteen billion, twenty-four million, five hundred fifty-one thousand, one hundred forty-seven".
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