2213040113 has 2 divisors, whose sum is σ = 2213040114. Its totient is φ = 2213040112.

The previous prime is 2213040043. The next prime is 2213040119. The reversal of 2213040113 is 3110403122.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2212103089 + 937024 = 47033^2 + 968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2213040113 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 2213040091 and 2213040100.

It is not a weakly prime, because it can be changed into another prime (2213040119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1106520056 + 1106520057.

It is an arithmetic number, because the mean of its divisors is an integer number (1106520057).

Almost surely, 2^2213040113 is an apocalyptic number.

It is an amenable number.

2213040113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2213040113 is an equidigital number, since it uses as much as digits as its factorization.

2213040113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 2213040113 is about 47042.9602916313. The cubic root of 2213040113 is about 1303.1560620759.

Adding to 2213040113 its reverse (3110403122), we get a palindrome (5323443235).

The spelling of 2213040113 in words is "two billion, two hundred thirteen million, forty thousand, one hundred thirteen".