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22135433 is a prime number
BaseRepresentation
bin101010001110…
…0001010001001
31112122121002212
41110130022021
521131313213
62110234505
7356101535
oct124341211
945577085
1022135433
1111549751
1274b5a35
1347803b8
142d22bc5
151e239a8
hex151c289

22135433 has 2 divisors, whose sum is σ = 22135434. Its totient is φ = 22135432.

The previous prime is 22135429. The next prime is 22135441. The reversal of 22135433 is 33453122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17330569 + 4804864 = 4163^2 + 2192^2 .

It is a cyclic number.

It is not a de Polignac number, because 22135433 - 22 = 22135429 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 22135399 and 22135408.

It is not a weakly prime, because it can be changed into another prime (22135403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11067716 + 11067717.

It is an arithmetic number, because the mean of its divisors is an integer number (11067717).

Almost surely, 222135433 is an apocalyptic number.

It is an amenable number.

22135433 is a deficient number, since it is larger than the sum of its proper divisors (1).

22135433 is an equidigital number, since it uses as much as digits as its factorization.

22135433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2160, while the sum is 23.

The square root of 22135433 is about 4704.8308152366. The cubic root of 22135433 is about 280.7777399272. Note that the first 4 decimals are identical.

Adding to 22135433 its reverse (33453122), we get a palindrome (55588555).

The spelling of 22135433 in words is "twenty-two million, one hundred thirty-five thousand, four hundred thirty-three".