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221411706474443 is a prime number
BaseRepresentation
bin110010010101111101101110…
…000111010000111111001011
31002000221202022111212212200112
4302111331232013100333023
5213010102133324140233
62102523044520424535
764431316330360532
oct6225755607207713
91060852274785615
10221411706474443
11646041a5128141
12209bb0a461814b
13967105a56c424
143c965530dd319
151a8e65eb75048
hexc95f6e1d0fcb

221411706474443 has 2 divisors, whose sum is σ = 221411706474444. Its totient is φ = 221411706474442.

The previous prime is 221411706474407. The next prime is 221411706474461. The reversal of 221411706474443 is 344474607114122.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-221411706474443 is a prime.

It is a super-2 number, since 2×2214117064744432 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 221411706474391 and 221411706474400.

It is not a weakly prime, because it can be changed into another prime (221411706474143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110705853237221 + 110705853237222.

It is an arithmetic number, because the mean of its divisors is an integer number (110705853237222).

Almost surely, 2221411706474443 is an apocalyptic number.

221411706474443 is a deficient number, since it is larger than the sum of its proper divisors (1).

221411706474443 is an equidigital number, since it uses as much as digits as its factorization.

221411706474443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3612672, while the sum is 50.

The spelling of 221411706474443 in words is "two hundred twenty-one trillion, four hundred eleven billion, seven hundred six million, four hundred seventy-four thousand, four hundred forty-three".