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221424113 is a prime number
BaseRepresentation
bin11010011001010…
…10100111110001
3120102122111210002
431030222213301
5423141032423
633545515345
75326034231
oct1514524761
9512574702
10221424113
11103a96239
12621a2b55
1336b489b1
142159bcc1
151468c228
hexd32a9f1

221424113 has 2 divisors, whose sum is σ = 221424114. Its totient is φ = 221424112.

The previous prime is 221424101. The next prime is 221424127. The reversal of 221424113 is 311424122.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 154952704 + 66471409 = 12448^2 + 8153^2 .

It is a cyclic number.

It is not a de Polignac number, because 221424113 - 222 = 217229809 is a prime.

It is not a weakly prime, because it can be changed into another prime (221421113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110712056 + 110712057.

It is an arithmetic number, because the mean of its divisors is an integer number (110712057).

Almost surely, 2221424113 is an apocalyptic number.

It is an amenable number.

221424113 is a deficient number, since it is larger than the sum of its proper divisors (1).

221424113 is an equidigital number, since it uses as much as digits as its factorization.

221424113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 384, while the sum is 20.

The square root of 221424113 is about 14880.3263741089. The cubic root of 221424113 is about 604.9808640898.

Adding to 221424113 its reverse (311424122), we get a palindrome (532848235).

Subtracting 221424113 from its reverse (311424122), we obtain a palindrome (90000009).

The spelling of 221424113 in words is "two hundred twenty-one million, four hundred twenty-four thousand, one hundred thirteen".