Base | Representation |
---|---|
bin | 100000001110010000011… |
… | …011101000101111110011 |
3 | 21211200120120001002110102 |
4 | 200032100123220233303 |
5 | 242234422304240311 |
6 | 4413125541023015 |
7 | 315660123451013 |
oct | 40162033505763 |
9 | 7750516032412 |
10 | 2214331321331 |
11 | 7841023378a8 |
12 | 2b919b0b4a6b |
13 | 130a6ca0872c |
14 | 79262051c43 |
15 | 3c8ee6ce43b |
hex | 203906e8bf3 |
2214331321331 has 2 divisors, whose sum is σ = 2214331321332. Its totient is φ = 2214331321330.
The previous prime is 2214331321289. The next prime is 2214331321351. The reversal of 2214331321331 is 1331231334122.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2214331321331 - 214 = 2214331304947 is a prime.
It is a super-2 number, since 2×22143313213312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2214331321294 and 2214331321303.
It is not a weakly prime, because it can be changed into another prime (2214331321351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1107165660665 + 1107165660666.
It is an arithmetic number, because the mean of its divisors is an integer number (1107165660666).
Almost surely, 22214331321331 is an apocalyptic number.
2214331321331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2214331321331 is an equidigital number, since it uses as much as digits as its factorization.
2214331321331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776, while the sum is 29.
Adding to 2214331321331 its reverse (1331231334122), we get a palindrome (3545562655453).
The spelling of 2214331321331 in words is "two trillion, two hundred fourteen billion, three hundred thirty-one million, three hundred twenty-one thousand, three hundred thirty-one".
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