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221536051401347 is a prime number
BaseRepresentation
bin110010010111110001100001…
…101001100001001010000011
31002001101122021022210122101122
4302113301201221201022003
5213014121313124320342
62103100131304022455
764443310605664364
oct6227614151411203
91061348238718348
10221536051401347
1164651a03646141
1220a1b207461a2b
13967c9b5976257
143c9c58b505b6b
151a929db2d64d2
hexc97c61a61283

221536051401347 has 2 divisors, whose sum is σ = 221536051401348. Its totient is φ = 221536051401346.

The previous prime is 221536051401319. The next prime is 221536051401359. The reversal of 221536051401347 is 743104150635122.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-221536051401347 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 221536051401298 and 221536051401307.

It is not a weakly prime, because it can be changed into another prime (221536051401377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 110768025700673 + 110768025700674.

It is an arithmetic number, because the mean of its divisors is an integer number (110768025700674).

Almost surely, 2221536051401347 is an apocalyptic number.

221536051401347 is a deficient number, since it is larger than the sum of its proper divisors (1).

221536051401347 is an equidigital number, since it uses as much as digits as its factorization.

221536051401347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 604800, while the sum is 44.

The spelling of 221536051401347 in words is "two hundred twenty-one trillion, five hundred thirty-six billion, fifty-one million, four hundred one thousand, three hundred forty-seven".