Base | Representation |
---|---|
bin | 10100101011011111… |
… | …000100011100011001 |
3 | 2010022110111110112021 |
4 | 110223133010130121 |
5 | 330433311321213 |
6 | 14111153214441 |
7 | 1414150204144 |
oct | 245337043431 |
9 | 63273443467 |
10 | 22204401433 |
11 | 9464895495 |
12 | 4378261421 |
13 | 212b2ba796 |
14 | 1108d8b05b |
15 | 89e556d8d |
hex | 52b7c4719 |
22204401433 has 8 divisors (see below), whose sum is σ = 23769208800. Its totient is φ = 20679209568.
The previous prime is 22204401421. The next prime is 22204401511. The reversal of 22204401433 is 33410440222.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 22204401433 - 29 = 22204400921 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 22204401398 and 22204401407.
It is not an unprimeable number, because it can be changed into a prime (22204401413) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9902716 + ... + 9904957.
It is an arithmetic number, because the mean of its divisors is an integer number (2971151100).
Almost surely, 222204401433 is an apocalyptic number.
It is an amenable number.
22204401433 is a deficient number, since it is larger than the sum of its proper divisors (1564807367).
22204401433 is a wasteful number, since it uses less digits than its factorization.
22204401433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19807751.
The product of its (nonzero) digits is 4608, while the sum is 25.
Adding to 22204401433 its reverse (33410440222), we get a palindrome (55614841655).
The spelling of 22204401433 in words is "twenty-two billion, two hundred four million, four hundred one thousand, four hundred thirty-three".
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